isbn手机屏幕号码查询，isbn编号是书号码

在这里插入代码片```s = input()s1 = ss = list(s)s1 = list(s1)s2 = ""n = len(s)m = 0while n != 0: if '-' in s: s.remove('-') n = n - 1for i in range(len(s)-1): s[i] = int(s[i]) m = m + s[i] * (i + 1)m1 = m % 11if str(m1) == s[-1]: print("Right")elif m1 == 10 and s[-1] == 'X': print("Right")else: if m1 == 10: s1.pop() s1.append('X') print(s2.join(s1)) else: s1.pop() s1.append(str(m1)) print(s2.join(s1)) 刚刚入门Python,用CCF的题来练习，hhdkl一个，代码写的不够简洁，请大神多多指教 60326099