该楼层疑似违规已被系统折叠?隐藏此楼查看此楼
程序如下
gama = 2*pi/9;
h = 300;
Rr = 400;
R1 = h/(2*sin(gama/2));
theta1 = linspace(0,gama/8,10);
theta2 = linspace(gama/8,gama/4,10);
theta3 = linspace(gama/4,3*gama/8,10);
theta4 = linspace(3*gama/8,gama/2,10);
theta5 = linspace(gama/2,5*gama/8,10);
theta6 = linspace(5*gama/8,3*gama/4,10);
theta7 = linspace(3*gama/4,7*gama/8,10);
theta8 = linspace(7*gama/8,gama,10);
theta = [theta1 theta2 theta3 theta4 theta5 theta6 theta7 theta8];
c1 = -R1.*(sin(gama-theta)+sin(theta)); c2 = R1.*(cos(gama-theta)-cos(theta)); c3 = -h^2*sin(theta)./(sin(gama-theta)+sin(theta))+h^2/2-... R1^2*sin(gama).*(cos(gama-theta)-cos(theta))./(sin(gama-theta)+sin(theta)); c5 = h.*sin(theta)./(sin(gama-theta)+sin(theta)); YY4 = [Y4(1) Y4(2) Y4(3) Y4(4) Y4(5) Y4(6) Y4(7) Y4(8) Y4(9) ceil(Y4(10))]; Y =[Y11 Y22]; Z = [Z1 Z2]; X = -c3./c1-h./c1.*Z-c2./c1.*Y; R1 = h/(2*sin(gama/2)); Xc = 0; Yc = R1*sin(gama)./(sin(gama-theta)+sin(theta)); Zc = h*sin(theta)./(sin(gama-theta)+sin(theta))-h/2; r = sqrt((X-Xc).^2+(Y-Yc).^2+(Z-Zc).^2); plot(theta,r) 谢谢各位大哥,想要实现的就是将r绕theta轴进行旋转,成为空间曲面